Tiling with arbitrary tiles
Vytautas Gruslys, Imre Leader, Ta Sheng Tan · Proceedings of the London Mathematical Society · 2016
Let T be a tile in Z n , meaning a finite subset of Z n . It may or may not tile Z n , in the sense of Z n having a partition into copies of T. However, we prove that T does tile Z d for some d. This resolves a conjecture of Chalcraft.