Improving usage statistics for RepositóriUM
Elóy Rodrigues, Ângelo Miranda, Ricardo Saraiva · Portuguese National Funding Agency for Science, Research and Technology (RCAAP Project by FCT) · 2007
[IN THIS RECORD ONLY FOR EXAMPLE PURPOSES] #### >This is a Markdown sample! < **And the following a MathJax sample:** $$1+2=3$$ $$\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$$ Same thing inline: $\sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6}$ When $a e 0$, there are two solutions to $ax^2 + bx + c = 0$ and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ $$\begin{array}{c} abla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} abla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\ abla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\ abla \cdot \vec{\mathbf{B}} & = 0 \end{array}$$ $$ A=\begin{bmatrix} a & b\\ c & d\\ e & f \end{bmatrix}$$ $$ \begin{equation} \label{eq:bayes} P(\theta|\textbf{D}) = P(\theta ) \frac{P(\textbf{D} |\theta)}{P(\textbf{D})} \end{equation} $$ The following but should be rendered as an error because it defines a duplicate equation label $$ \begin{equation} \label{eq:bayes} P(\theta|\textbf{D}) = P(\theta ) \frac{P(\textbf{D} |\theta)}{P(\textbf{D})} \end{equation} $$